Question
I need help solving this equation. 7y+5/3 = -8/y-3. I am stuck. please help me.
Answers
Steve
I will assume the usual carelessness with parentheses, and that you mean
(7y+5)/3 = -8/(y-3)
Clear fractions (assuming y≠3) and we have
(7y+5)(y-3) = -8(3)
7y^2 - 16y - 15 = -24
7y^2 - 16y + 9 = 0
(7y-9)(y-1) = 0
y = 1 or 9/7
(7y+5)/3 = -8/(y-3)
Clear fractions (assuming y≠3) and we have
(7y+5)(y-3) = -8(3)
7y^2 - 16y - 15 = -24
7y^2 - 16y + 9 = 0
(7y-9)(y-1) = 0
y = 1 or 9/7