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Asked by frederick

in a certain distribution the mean is 68, with a variance of 16. Using chebyshev's theorem at least what percentage of values will fall between 60 and 76
11 years ago

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Answered by PsyDAG
SD = √variance

Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability between your Z scores.
11 years ago

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