Asked by Kaylee
A single constant force 18.1 N acts on a particle of mass 2.92 kg. The particle starts at rest at t=0. What is the instantaneous power delivered by the force at t=4.48s? Answer in units of W
Answers
Answered by
Henry
a = F/m = 18.1/2.92 = 6.20 m/s^2.
V = Vo + a*t = 0 + 6.20*4.48 = 27.77 m/s
P=F*(d/t) = F*V = 18.1 * 27.77=502.6 J/s
= 502.6 Watts.
V = Vo + a*t = 0 + 6.20*4.48 = 27.77 m/s
P=F*(d/t) = F*V = 18.1 * 27.77=502.6 J/s
= 502.6 Watts.
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