Find the area bounded by the line y = 1 and the curve y = x^2 - 3.

Question

Answer

8/3

16/3

32/3

32

Answer 1

Since the curve intersects the line at (-2,1) and (2,1), we can use vertical strips to get

a = ∫[-2,2] 1 - (x^2-3) dx = 32/3

Or, we can use horizontal strips to get

x = ±√(y+3)
a = ∫[-3,1] √(y+3) - (-√(y+3)) dy = 32/3