Asked by Kaylee
A car and driver weighing 7750 N passes a sign stating “Bridge Out 28.5 m Ahead.” She slams on the brakes, and the car decelerates at a constant rate of 10.6 m/s2 .
The acceleration of gravity is 9.8 m/s2 .
What is the magnitude of the work done stopping the car if the car just stops in time to avoid diving into the water?
Answer in units of J
The acceleration of gravity is 9.8 m/s2 .
What is the magnitude of the work done stopping the car if the car just stops in time to avoid diving into the water?
Answer in units of J
Answers
Answered by
MathMate
Using Newton's second law F=ma
to find the mass, then again the same law to find the frictional force.
Finally use Work done = F.D
Units are in kg, m/s² and J.
Mass m = 7750/9.8 = 790.82 kg
Frictional force = ma
= 790.82 kg * 10.6 m/s²
= 8382.7 N
Work done (assuming uniform frictional foce)
= F.D
= 8382.7 N * 28.5 m
= 238906 J
= 238.9 kJ
to find the mass, then again the same law to find the frictional force.
Finally use Work done = F.D
Units are in kg, m/s² and J.
Mass m = 7750/9.8 = 790.82 kg
Frictional force = ma
= 790.82 kg * 10.6 m/s²
= 8382.7 N
Work done (assuming uniform frictional foce)
= F.D
= 8382.7 N * 28.5 m
= 238906 J
= 238.9 kJ
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.