Asked by Anonymous
Given the area of ABC=7.52m^2. Find a to the nearest hundredth meter when m<B=40 degrees and c=6m
Answers
Answered by
Steve
If h is the altitude from C to AB, we have
1/2 * ch = 3h = 7.52
So, h = 2.507
Now h/a = sin 40°
a = 2.507/0.642 = 3.90
1/2 * ch = 3h = 7.52
So, h = 2.507
Now h/a = sin 40°
a = 2.507/0.642 = 3.90
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.