a. What is 12*44/molmasssugar
b. mole )2= molessugar*12
The equation for the reaction of sucrose(sugar)with oxygen is C12H22O11+12O2--->12CO2+11H2O
how many g of co2 is produced per g of sucrose used?how many mol of oxygen gas is needed to react with 1.0g sucrose?(C12H22O11=342g/mol)
2 answers
Dear akhmal,
mol of sucrose used=
1/(12x12 + 22 + 11X16)
= 2.92x10^-3
as 1 mole of sucrose will produce 12 moles of Co2
mol of CO2 produced= (2.92x10^-3)X 12
= 0.035
grams of CO2 produced = 0.035 X (12+32)
= 1.54g
as 1 mole of sucrose will react with 12 moles of o2
mole of O2 needed= (2.92x10^-3)X 12
= 0.035087719
mol of sucrose used=
1/(12x12 + 22 + 11X16)
= 2.92x10^-3
as 1 mole of sucrose will produce 12 moles of Co2
mol of CO2 produced= (2.92x10^-3)X 12
= 0.035
grams of CO2 produced = 0.035 X (12+32)
= 1.54g
as 1 mole of sucrose will react with 12 moles of o2
mole of O2 needed= (2.92x10^-3)X 12
= 0.035087719
1 answer