Asked by iz
A golfer sees the green (where the hole is) at a distance of 120.0 m at heading 75.0° north of west. She also sees her teammate at a distance of 60.0 m and heading 15.0° north of east.
What distance and direction would her teammate have to land the ball to hit the green?
What distance and direction would her teammate have to land the ball to hit the green?
Answers
Answered by
MathMate
Magnitude:use Pythagoras theorem (note 90° between the teammate and the green).
Angle (from point of view of teammate)
= atan(120/60)+75° West of south
since the golfer is at 75° west of south from the point of view of the teammate.
Angle (from point of view of teammate)
= atan(120/60)+75° West of south
since the golfer is at 75° west of south from the point of view of the teammate.
Answered by
Henry
d = d2-d1 = 120m[105o]-60m[15o]
X = 120*cos105 - 60*cos15 = -89.0 m.
Y = 120*sin105 - 60*sin15 = 100.4 m.
Tan Ar = Y/X = 100.4/-89.0 = -1.12789
Ar = -48.44o = Reference angle.
A = -48.44 + 180 = 131.6o = Direction.
d = Y/sinA = 100.4/sin131.6 = 134.3 m.
[131.6].
X = 120*cos105 - 60*cos15 = -89.0 m.
Y = 120*sin105 - 60*sin15 = 100.4 m.
Tan Ar = Y/X = 100.4/-89.0 = -1.12789
Ar = -48.44o = Reference angle.
A = -48.44 + 180 = 131.6o = Direction.
d = Y/sinA = 100.4/sin131.6 = 134.3 m.
[131.6].
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