Dear Sally,
as I have replied you before, I am not sure whether you have checked
HCL(aq) + NAOH(aq)---- NACL(s)+ H20(l)
Number of moles in the NAOH(aq)=
40/(23+16+1)
=1
as 1 mole of HCL will react with 1 mole of the Naoh solution
number of mole of HCL required= 1
Still remember that there is a equation
mol= g/molar mass
Let the number of grams of HCL needed be g grams
the number of grams of HCL required=
1= g/(1+35.5)
g=36.5
Therefore, 36.5 grams of HCL is required
For the grams of Nacl produced
1 mole of Hcl will produce 1 mole of nacl
Let the number of grams of salt produced be g grams
1x(23+35.5)
=55.5
Therefore 55.5 grams of nacl is produced
For the grams of water produced
1 mole of Hcl will produce 1 mole of water
Let the number of gram of the water produced be g grams
so 1= g/18
g=18
Therefore, 18 grams of water is produced