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Find the probability of P(E or F) if E and F are mutually exclusive P(E)=0.41 and P(F)=0.47

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P(E∪F)=P(E)+P(F)-P(E∩F)
If E and F are mutually exclusive (ME), then P(E∩F)=0, and consequently
P(E∪F)=P(E)+P(F)=0.41+0.47=0.88

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