Asked by shish
find (i) the total no. of neutrons and (ii) the total mass of neutrons in 7mg o^14C. (assume that the mass of a neutron = mass of a hydrogen atom)
Answers
Answered by
DrBob222
mols = grams/molar mass
0.007g/14 = ? mols C14 atoms
There are 7 neutrons/atom; therefore,
# mols x 7 = ? mols neutrons.
There are 6.02E23 neutrons for each mol of neutrons; therefore,
mols neutrons x 6.02E23 neutrons/mol = # neutrons.
mass of those neutrons = # neutrons x mass of H atom.
0.007g/14 = ? mols C14 atoms
There are 7 neutrons/atom; therefore,
# mols x 7 = ? mols neutrons.
There are 6.02E23 neutrons for each mol of neutrons; therefore,
mols neutrons x 6.02E23 neutrons/mol = # neutrons.
mass of those neutrons = # neutrons x mass of H atom.
Answered by
Uma
In 14g of 14^C,no.of neutrons =8NA
In 1g of 14C,no.of neutrons =8NA/14
1)the total no.of neutrons in 7mg of 14^C= 7/1000×4/7×6×10^20
=24×10^20
2)given mass of a neutron=mass of 1 Hydrogen atom=1 amu
Mass of 24×10^20 neutrons=1×24×10^20×1.6×10^-24 g
=0.0004 g
In 1g of 14C,no.of neutrons =8NA/14
1)the total no.of neutrons in 7mg of 14^C= 7/1000×4/7×6×10^20
=24×10^20
2)given mass of a neutron=mass of 1 Hydrogen atom=1 amu
Mass of 24×10^20 neutrons=1×24×10^20×1.6×10^-24 g
=0.0004 g
Answered by
Prateek
Are you from resonance?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.