Question

A 5kg crate falls from height of 2 m into an industrial spring scale. When the crate comes to rest the compression of the spring is 25 cm what is the spring constant?

Answers

Damon
loss of gravitational potential energy
= m g * change in height
= 5 * 9.81 *(2 + .25)
= 110 Joules
that is now stored in the spring (1/2)kx^2
so
(1/2) k (.25)^2 = 110

k = 3532 N/m

Related Questions