Asked by Sheenybeany
How do you find the altitudes of a right triangle with the three sides?
Answers
Answered by
MathMate
If you just want the area, use Hero's formula:
Let
p = (a+b+c)/2 = half-perimeter
Area = √(p(p-a)(p-b)(p-c))
If it's really the altitude you need, then find each angle using the cosine law:
cos(A)=(b²+c²-a²)/(2bc)
where a,b,c are lengths of sides opposite to the respective angles A, B and C. Altitudes are AD, BE, CF.
Altitude CF can be found by b*sin(A), etc.
Let
p = (a+b+c)/2 = half-perimeter
Area = √(p(p-a)(p-b)(p-c))
If it's really the altitude you need, then find each angle using the cosine law:
cos(A)=(b²+c²-a²)/(2bc)
where a,b,c are lengths of sides opposite to the respective angles A, B and C. Altitudes are AD, BE, CF.
Altitude CF can be found by b*sin(A), etc.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.