A person standing on top of a building throws a ball with a horizontal velocity of 14 m/s. If the ball strikes the ground 65 m from the base of the building, how high is the building?

2 answers

distance = speed * time with no force in horizontal direction

65 = 14 t
t = 4.64 seconds in the air

In the vertical direction it simply falls a distance h

h = (1/2) g t^2 = 4.9 (4.64^2)

h = 106 m
#dont know )= sorry, i knowed it but i forgot