Asked by Yogesh
an ice block at 0 degree celcius is dropped from height 'h' above the ground. what should be the value of 'h' so that it just melts completely by the time it reaches the bottom assuming the loss of whole gravitational potential energy is used as heat by the ice ? (given: Lf = 80 cal/gm )
Answers
Answered by
Damon
80 cal = 335 joules
so Lf = 335 Joules / .001 kg - 335,000 Joules/kg
potential energy = m g h
m g h = m (335,000)
9.81 h = 335,000
h = 34,149 meters
so Lf = 335 Joules / .001 kg - 335,000 Joules/kg
potential energy = m g h
m g h = m (335,000)
9.81 h = 335,000
h = 34,149 meters
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