Question

A 7.50 kg bowling ball strikes a stationary 4.50 kg bowling ball. After the collision, the 4.50 kg
ball is traveling 8.50 m/s 30.0° east of north; the 7.50 kg ball is traveling 6.50 m/s 20.0° south of
east. What was the initial velocity (magnitude and direction) of the 7.50 kg ball?

Answer 1

North south problem
7.5 Vn = 4.5 (8.5 cos 30) -7.5(6.5 sin 20)

East west problem
7.5 Ve = 4.5(8.5 sin 30) +7.5(6.5 cos 20)