Asked by Me and I
Am i Correct?
2.0 cm*.044T*/.10 s= 0.88 V
Each side of a square loop of wire measures 2.0 cm. A magnetic field of 0.044 T perpendicular to the loop changes to zero in 0.10 s. What average emf is induced in the coil during this change?
A. 1.8 V
B. 0.088 V
C. 0.88 V <--
D. 0.00018 V
2.0 cm*.044T*/.10 s= 0.88 V
Each side of a square loop of wire measures 2.0 cm. A magnetic field of 0.044 T perpendicular to the loop changes to zero in 0.10 s. What average emf is induced in the coil during this change?
A. 1.8 V
B. 0.088 V
C. 0.88 V <--
D. 0.00018 V
Answers
Answered by
Damon
area of loop = .02^2 = .0004 m^2
dB/dt = .044/.1 = .44
emf = A dB/dt = .0004 *.44 = 1.76 * 10^-4 = .00018 V
dB/dt = .044/.1 = .44
emf = A dB/dt = .0004 *.44 = 1.76 * 10^-4 = .00018 V
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.