Asked by Victor
Finding three geometrically numbers knowing that their sum is greater than 78 and 30 units exceeds the sum of the other two.
Answers
Answered by
Reiny
strange wording ....
" Finding three geometrically numbers"
I assume you have 3 numbers in a geometric sequence.
"30 units exceeds the sum of the other two"
...... which "other two" , the first two, the last two , or the middle two ?
the three numbers are:
a, ar, and ar^2
a + ar + ar^2 > 78
I will assume that 30 exceeds the sum of the first two
30 > a + ar
a(1+r) < 30 and a(1+r + r^2) > 78
I will continue once you clarify your question.
" Finding three geometrically numbers"
I assume you have 3 numbers in a geometric sequence.
"30 units exceeds the sum of the other two"
...... which "other two" , the first two, the last two , or the middle two ?
the three numbers are:
a, ar, and ar^2
a + ar + ar^2 > 78
I will assume that 30 exceeds the sum of the first two
30 > a + ar
a(1+r) < 30 and a(1+r + r^2) > 78
I will continue once you clarify your question.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.