Asked by kabhir
if 2x^3-5x^2+x+2=(x-2)(ax^2-bx-1)then a and b are respectively:
Answers
Answered by
Henry
Use synthetic(long-hand) division:
(2x^3-5x^2+x+2)/(x-2) = 2x^2-x-1
a = 2, and b = -1.
(2x^3-5x^2+x+2)/(x-2) = 2x^2-x-1
a = 2, and b = -1.
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