Asked by Jamie
Assume v(t) = 6t - 18 on the interval [0, 6]. Find the total distance that the object traveled on [0, 6].
Answers
Answered by
Steve
we just did one of these
x(t) = 3t^2 - 18t + c
Now just figure x(6)-x(0)
x(t) = 3t^2 - 18t + c
Now just figure x(6)-x(0)
Answered by
Jamie
I got 0. That doesn't make sense to me...
x(0) = 3(0)^2 - 18(0) + C = 0+C
x(6) = 3(6)^2 - 18(6) + C = 108-108+C = 0+C
x(6)-x(0)=0
x(0) = 3(0)^2 - 18(0) + C = 0+C
x(6) = 3(6)^2 - 18(6) + C = 108-108+C = 0+C
x(6)-x(0)=0
Answered by
Damon
Your velocity is zero at t = 3 !!!!!
right in the middle of your range.
It reversed direction midstream
You calulated displacement (where it moved to which was nowhere)
instead of how far it went (distance moved)
do t = 0 to t = 3
then t = 3 to t = 6
add the ABSOLUTE VALUES
right in the middle of your range.
It reversed direction midstream
You calulated displacement (where it moved to which was nowhere)
instead of how far it went (distance moved)
do t = 0 to t = 3
then t = 3 to t = 6
add the ABSOLUTE VALUES
Answered by
Damon
See Baggins, Bilbo, "There and Back Again".
Answered by
Jamie
So is the total distance 54?
Answered by
Damon
yes
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