Asked by Molly
I need help on these three questions. For all three of them you're supposed to write a balanced equation for each neutralization. Then, to find the concentrations of the unknown solutions if the following reactions are found to reach equivalence by titration.
The three questions are:
5) 21.7 mL of 0.0500 M Ba(OH)2 is added to 35.0 mL of HCl of unknown concentration.
6) 25.0 mL of 0.200 M lithium hydroxide is added to 20.0 mL of phosphoric acid of unknown concentration.
7) 30.0 mL of 0.500 M hydrobromic acid is added to 38.0 mL of strontium hydroxide of unknown concentration.
The three questions are:
5) 21.7 mL of 0.0500 M Ba(OH)2 is added to 35.0 mL of HCl of unknown concentration.
6) 25.0 mL of 0.200 M lithium hydroxide is added to 20.0 mL of phosphoric acid of unknown concentration.
7) 30.0 mL of 0.500 M hydrobromic acid is added to 38.0 mL of strontium hydroxide of unknown concentration.
Answers
Answered by
DrBob222
First, there is no way for me to know if these titrations have reached the equivalence point since the concn is unknown; however, I suspect what you really want to know is the concn of the unknown material
Ba(OH)2 + 2HCl ==> 2H2O + BaCl2
mols Ba(OH)2 = M x L = 0.0217 x 0.05 = apprx 0.00108
Using the coefficients in the balanced equation, convert mols Ba(OH)2 to mols HCl. That's 0.00108 mols Ba(OH)2 x (2 mols HCl/1 mol Ba(OH)2) = 0.00216
Then M HCl = mols HCl/L HCl = 0.00216/0.035 = apprx 0.062 but you need to go through and get these numbers more accurately.
6 and 7 are done the same way but I would point out on #6 that you don't indicate how many of the H ions in H3PO4 have been titrated.
Ba(OH)2 + 2HCl ==> 2H2O + BaCl2
mols Ba(OH)2 = M x L = 0.0217 x 0.05 = apprx 0.00108
Using the coefficients in the balanced equation, convert mols Ba(OH)2 to mols HCl. That's 0.00108 mols Ba(OH)2 x (2 mols HCl/1 mol Ba(OH)2) = 0.00216
Then M HCl = mols HCl/L HCl = 0.00216/0.035 = apprx 0.062 but you need to go through and get these numbers more accurately.
6 and 7 are done the same way but I would point out on #6 that you don't indicate how many of the H ions in H3PO4 have been titrated.
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