Asked by Jack
The average weight of 3 boys is 53 pounds. Not one of these boys weighs less than 51 pounds. What is the maximum possible weight in pounds, of any one boy?
Answers
Answered by
Steve
If two weigh 51, that's the minimum for two boys, leaving the maximum for the 3rd boy of
3*159-2*51 = 159-102 = 57
3*159-2*51 = 159-102 = 57
Answered by
Hiba
Can u plz explain me in easy way.i don't understand the calculation
Answered by
Hiba
You wrote 3*159-2*51=159-102=57
So my question is that why are you putting 159 . This is even not in the question
So my question is that why are you putting 159 . This is even not in the question
Answered by
Jadulal Sutradhar
3*53 implies 159
Answered by
Mr. Shah
51+51+x/3=53
51+51+x=159
102+x=159
X= 159-102
X= 57
Answer
51+51+x=159
102+x=159
X= 159-102
X= 57
Answer
Answered by
Aqib Abbasi
ANY ONE FROM SZABIST UNIVERSITY (HYD)
Answered by
Likhon das
Why take Two times is 51? you can take 52 or other...can you explain this please?
Answered by
T
Tfd
Answered by
Damon
x+y+z = 53*3 = 159
if y+z = 51*2 = 102 (min x and y possible to get max x)
then x = 159 - 102 = 57
if y+z = 51*2 = 102 (min x and y possible to get max x)
then x = 159 - 102 = 57
Answered by
ronnie dion
400 +4000=
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