Asked by Ariana
The registration numbers of vehicles in a certain country use digits 1-999. If a visitor has just entered the country. What is the probability that the first car he sees has at least 2 identical digits?
Ans: 29/111
Ans: 29/111
Answers
Answered by
MathMate
Assuming leading zeroes count as digits, then probability of seeing 3 distinct digits
= 10*9*8/1000
= 720/1000
=18/25
Probability of at least 2 identical digits
= 280/1000
=7/25
If leading zeroes are not displayed, then
there are 9*9*8=648 plates with distinct digits between 100-999
and 90 between 1 and 99
for a total of 738 out of 999 plates.
So probability of plates with at least 2 identical digits is
(999-738)/999
=29/11
= 10*9*8/1000
= 720/1000
=18/25
Probability of at least 2 identical digits
= 280/1000
=7/25
If leading zeroes are not displayed, then
there are 9*9*8=648 plates with distinct digits between 100-999
and 90 between 1 and 99
for a total of 738 out of 999 plates.
So probability of plates with at least 2 identical digits is
(999-738)/999
=29/11
Answered by
MathMate
Last line should read
29/111
29/111
Answered by
Ariana
How do you get 738/999??
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