A 49-g bullet traveling at 290m/s penetrates a block of ice at 0∘C and comes to rest within the ice.Assuming that the temperature of the bullet doesn't change appreciably, how much ice is melted as a result of the collision? The heat of fusion of water is 333 kJ/kg.

Answer 1

Equate energy with the heat of fusion of water.

(1/2)mv²=MH
m=mass of bullet(kg)
H=heat of fusion (J/kg)
M=mass of ice melted (kg)

Make sure the heat of fusion of water is converted to J/kg for your calculations.