A 55 kg skateboarder accelerates down a ramp and hits the pavement moving at 5.6 m/s. If the pavement has a coefficient of friction of 0.11, how far will skateboarder glide before coming to a stop?

Answer 1

normal force = 55 g
friction force = .11 * 55 g

acceleration = F/m = -.11 * 55 * g /55
= -.11 g = -1.08 m/s^2

v = Vi + a t
0 = 5.6 - 1.08 t
t = 5.2 seconds to stop
go at average speed (5.6 /2) for 5.2 seconds
d = 14.5 meters