Asked by Anonymous
Solve the equation 6(1/x)^2-7(1/x)+2=0
Answers
Answered by
MathMate
Here we see that x cannot be zero, so replace (1/x) by y and solve the resulting quadratic.
6y²-7y+2=0
(2y-1)(3y-2)=0
y=1/2 or y=2/3
find x from y=1/x, or x=1/y
x=2, or x=3/2
6y²-7y+2=0
(2y-1)(3y-2)=0
y=1/2 or y=2/3
find x from y=1/x, or x=1/y
x=2, or x=3/2
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