Asked by Anonymous
Solve the equation x^2/5 + x^1/5 -6=0
Answers
Answered by
MathMate
BEDMAS tells us that exponents are evaluated before division, so the equation reads
(x²)/5 + x/5-6=0
Multiply by 5 to get
x²+x-30=0
(x-5)(x+6)=0
So x can be readily found.
(x²)/5 + x/5-6=0
Multiply by 5 to get
x²+x-30=0
(x-5)(x+6)=0
So x can be readily found.
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