Question
A 15.0 kΩ resistor is hooked up to a 45.0 V battery in a circuit with a switch.
a.) What is the current flowing through the resistor?
b.) What is the power dissipated by the resistor?
a.) What is the current flowing through the resistor?
b.) What is the power dissipated by the resistor?
Answers
MathMate
V=IR
I=V/R=45/15000=3*10<sup>-3</sup> A.
Power = VI joules
I=V/R=45/15000=3*10<sup>-3</sup> A.
Power = VI joules
MathMate
Power = VI watts