Asked by Me and I

A 15.0 kΩ resistor is hooked up to a 45.0 V battery in a circuit with a switch.

a.) What is the current flowing through the resistor?
b.) What is the power dissipated by the resistor?
Answered by MathMate
V=IR
I=V/R=45/15000=3*10<sup>-3</sup> A.
Power = VI joules
Answered by MathMate
Power = VI watts
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