Asked by nonononono
If 12 people are playing in a tournament and each person plays every other person, how many games will be played?
Answers
Answered by
nonononono
Mrs. Sue??
Answered by
nonononono
Reiny
Answered by
bobpursley
The first person plays 11, the second plays 10, the thrid plays 9
number games=11+10+9+...+1
the sum of numbers from n-1 to 1, or
number= N*(n-1)/2=12*11/2= 66
number games=11+10+9+...+1
the sum of numbers from n-1 to 1, or
number= N*(n-1)/2=12*11/2= 66
Answered by
Reiny
number of subsets of 2 elements from a sample space of 12
= C(12,2) = 66
= C(12,2) = 66
Answered by
aa
n*(n-1)/2
Answered by
Katharine
66 people. Just do 132 / 2.
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