Asked by nonononono

If 12 people are playing in a tournament and each person plays every other person, how many games will be played?
Answered by nonononono
Mrs. Sue??
Answered by nonononono
Reiny
Answered by bobpursley
The first person plays 11, the second plays 10, the thrid plays 9

number games=11+10+9+...+1
the sum of numbers from n-1 to 1, or
number= N*(n-1)/2=12*11/2= 66
Answered by Reiny
number of subsets of 2 elements from a sample space of 12
= C(12,2) = 66
Answered by aa
n*(n-1)/2
Answered by Katharine
66 people. Just do 132 / 2.
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