Asked by Jess
                n(n-1)-4
How do I solve stuff like this?
            
        How do I solve stuff like this?
Answers
                    Answered by
            Jess
            
    How would I also solve the following?
f(x)=x^2-4+3 what is the output of f(-3)?
    
f(x)=x^2-4+3 what is the output of f(-3)?
                    Answered by
            Steve
            
    Just use the distributive property:
n(n-1)-4
n*n - n*1 - 4
n^2-n-4
Since f(x) = x^2-4x+3, and you want f(-3), just replace all the x's with -3 and you have
f(-3) = (-3)^2 - 4(-3) + 3
= 9+12+3
= 24
    
n(n-1)-4
n*n - n*1 - 4
n^2-n-4
Since f(x) = x^2-4x+3, and you want f(-3), just replace all the x's with -3 and you have
f(-3) = (-3)^2 - 4(-3) + 3
= 9+12+3
= 24
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