Asked by Jess
n(n-1)-4
How do I solve stuff like this?
How do I solve stuff like this?
Answers
Answered by
Jess
How would I also solve the following?
f(x)=x^2-4+3 what is the output of f(-3)?
f(x)=x^2-4+3 what is the output of f(-3)?
Answered by
Steve
Just use the distributive property:
n(n-1)-4
n*n - n*1 - 4
n^2-n-4
Since f(x) = x^2-4x+3, and you want f(-3), just replace all the x's with -3 and you have
f(-3) = (-3)^2 - 4(-3) + 3
= 9+12+3
= 24
n(n-1)-4
n*n - n*1 - 4
n^2-n-4
Since f(x) = x^2-4x+3, and you want f(-3), just replace all the x's with -3 and you have
f(-3) = (-3)^2 - 4(-3) + 3
= 9+12+3
= 24