Asked by Anonymous
A rectangular garden is 20 ft longer than it is wide. Its area is 8000 ft{}^2. What are its dimensions?
w(w+20) = 8000
w^2+20w = 8000
w^2+20w-8000 = 0
(w-80)(w+100) = 0
w-80 = 0
w=80
or
w+100 = 0
w = -100
I think that x=80 makes more sense. However what would the length be if the width is equal to 80 in this problem ? please help Im stuck and am not sure what the final answer for this question would be.
w(w+20) = 8000
w^2+20w = 8000
w^2+20w-8000 = 0
(w-80)(w+100) = 0
w-80 = 0
w=80
or
w+100 = 0
w = -100
I think that x=80 makes more sense. However what would the length be if the width is equal to 80 in this problem ? please help Im stuck and am not sure what the final answer for this question would be.
Answers
Answered by
Steve
Excuse me? You already know that the length is 20 more than the width.
So, if the width is 80, the length is 100.
Sure enough, 80*100 = 8000
Or, since you know the width is 80, and area = length*width
8000 = 80 * length
length=100
Don't forget your algebra I now that you're taking college algebra.
So, if the width is 80, the length is 100.
Sure enough, 80*100 = 8000
Or, since you know the width is 80, and area = length*width
8000 = 80 * length
length=100
Don't forget your algebra I now that you're taking college algebra.
Answered by
Anonymous
Thank You. I guess I was over thinking the problem a bit!lol It's my first semester and everything's so new.
Thanks so much again
Thanks so much again
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