well, it is hard for me to graph here so
eliminate y by subtracting the second equation from the first
x^2 + 5 x -50 = 0
(x-5)(x+10) = 0
so
x = 5 or x = -10
if x = 5, then y = -10
if x = -10 then y = 35
What are the solutions to the system? (Hint: graphing is the easiest!)
y = x2 + 2x - 45
y = -3x + 5
3 answers
Next easiest is by comparison.
Solve the quadratic by factoring
-3x+5 = x² +2x -45
x²+5x-50=0
(x+10)(x-5)=0
x=5 or x=-10
Substitute x to find corresponding values of y.
Solve the quadratic by factoring
-3x+5 = x² +2x -45
x²+5x-50=0
(x+10)(x-5)=0
x=5 or x=-10
Substitute x to find corresponding values of y.
thank you peeps
1 answer