Asked by Anonymous
                The sum of three consecutive natural numbers is 651, find the numbers.
3*7*31
21*31=651
is what I put for my answer but that was incorrect on the homework. Please help me
Another Question I had problems with was :Your weekly paycheck is 25 percent less than your coworker's. Your two paychecks total 780. Find the amount of each paycheck.
let a equal the amount of the paycheck
25% of my paycheck is a*25%
coworker=a(a*25%)=a+(a*25%)=a*(25a/100)=a+(a+4)=4a+a/4=5a/4
780a+5a/4=780
4a+5a=3120
9a=3120/9
a=346
Please help
            
        3*7*31
21*31=651
is what I put for my answer but that was incorrect on the homework. Please help me
Another Question I had problems with was :Your weekly paycheck is 25 percent less than your coworker's. Your two paychecks total 780. Find the amount of each paycheck.
let a equal the amount of the paycheck
25% of my paycheck is a*25%
coworker=a(a*25%)=a+(a*25%)=a*(25a/100)=a+(a+4)=4a+a/4=5a/4
780a+5a/4=780
4a+5a=3120
9a=3120/9
a=346
Please help
Answers
                    Answered by
            Steve
            
    If the numbers are
x-1,x,x+1, then
3x = 651
x = 217
So, the numbers are 216,217,218
Don't know what was all that stuff with factors of 651. Looks like you need to study what "sum" and "consecutive" mean.
The two paychecks are p and .75p. So,
p + .75p = 780
1.75p = 780
p = 445.71
Your paycheck is 25% less, so it is 75% of the other. Once you got your answer, did you check to see whether it worked to satisfy the given conditions? That pseudo-algebra you threw up is meaningless.
    
x-1,x,x+1, then
3x = 651
x = 217
So, the numbers are 216,217,218
Don't know what was all that stuff with factors of 651. Looks like you need to study what "sum" and "consecutive" mean.
The two paychecks are p and .75p. So,
p + .75p = 780
1.75p = 780
p = 445.71
Your paycheck is 25% less, so it is 75% of the other. Once you got your answer, did you check to see whether it worked to satisfy the given conditions? That pseudo-algebra you threw up is meaningless.
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