Asked by Test
A bought some carrots and apples for $24.80. A carrot and an apple $0.90 altogether. She bought more carrots than apples. The cost of the extra number of carrots was $6.80. How many apples did A buy?
Answers
Answered by
bobpursley
1C+1A=.90
nC+mA=24.80
(n-m)C=6.80
nC-MC=6.80
subtract second and last equation
0C+M(A+C)=18.00
But A+C=.90
M=18/.9=20
M is the number of apples
nC+mA=24.80
(n-m)C=6.80
nC-MC=6.80
subtract second and last equation
0C+M(A+C)=18.00
But A+C=.90
M=18/.9=20
M is the number of apples
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