Asked by Gina
For all values x for which the terms are defined, fidnteh value(s) of k, 0<k<1, such that
cot(x/4) - cot(x) = [sin(kx)]/[sin(x/4)sin(x)]
PLEASEEEE HELP! ASAP!
cot(x/4) - cot(x) = [sin(kx)]/[sin(x/4)sin(x)]
PLEASEEEE HELP! ASAP!
Answers
Answered by
???
That is a very confusing question, you may want to reword that if you want an answer
Answered by
Reiny
the left side
= cot(x/4) - cot(x)
= [cos(x/4)/sin(x/4)] - cos(x)/sin(x)
= [sin(x)cos(x/4)- cos(x)sin(x/4)]/[sin(x/4)sin(x)]
= sin(x - x/4)/[sin(x/4)sin(x)]
comparing left side with right side, we notice the denominators are the same, so the numerator has to be the same
then sin(x - x/4) = sin (kx)
and x-x/4 = kx
3x/4 = kx
k = 3/4
= cot(x/4) - cot(x)
= [cos(x/4)/sin(x/4)] - cos(x)/sin(x)
= [sin(x)cos(x/4)- cos(x)sin(x/4)]/[sin(x/4)sin(x)]
= sin(x - x/4)/[sin(x/4)sin(x)]
comparing left side with right side, we notice the denominators are the same, so the numerator has to be the same
then sin(x - x/4) = sin (kx)
and x-x/4 = kx
3x/4 = kx
k = 3/4
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.