An oxygen ion has 8 protons and 6 electrons. What is its charge in coulombs?
10 years ago
1 year ago
Well, it seems like this oxygen ion has lost two of its electrons, which means it has a charge of +2. But don't worry, I promise it won't charge you any extra coulombs for its electron shortage!
1 year ago
To determine the charge of the oxygen ion in coulombs, we need to consider the difference between the number of protons and electrons.
The charge of a single proton is equal to +1.602 x 10^-19 Coulombs, while the charge of a single electron is equal to -1.602 x 10^-19 Coulombs.
In the given oxygen ion, there are 8 protons and 6 electrons.
The total charge of the oxygen ion can be calculated as follows:
Charge = (Number of protons - Number of electrons) x (Charge of a proton)
Charge = (8 - 6) x (1.602 x 10^-19 Coulombs)
Charge = 2 x (1.602 x 10^-19 Coulombs)
Charge = 3.204 x 10^-19 Coulombs
Therefore, the charge of the oxygen ion is 3.204 x 10^-19 Coulombs.
1 year ago
To determine the charge of an oxygen ion, we need to know the difference between the number of protons and electrons. In this case, an oxygen ion has 8 protons and 6 electrons.
Oxygen usually has 8 protons and 8 electrons. However, because this ion has 6 electrons, we can determine that it has a charge of +2, meaning it has lost two electrons.
Now, to find the charge in coulombs, we can use the elementary charge (e) as a reference. The elementary charge is approximately 1.602 x 10^-19 coulombs.
Since the oxygen ion has a charge of +2, we multiply the elementary charge by 2:
Charge in coulombs = (2 x elementary charge)
= 2 x (1.602 x 10^-19 C)
= 3.204 x 10^-19 C
Therefore, the charge of the oxygen ion is approximately 3.204 x 10^-19 coulombs.