Asked by danielle
A 1.6 km road rises 400 m. What is the angle of elevation of the road to the nearest degree?
Answers
Answered by
Reiny
rise/run
= 400/1600
= 1/4
= tan Ø
Ø = appr 14°
= 400/1600
= 1/4
= tan Ø
Ø = appr 14°
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