F = - k x
= -130 (.1) = -13 N
if they do not slip m = 6.25 kg
a = 13/6.25 = 2.08 m/s^2
force required to accelerate small block = 1.25 *2.08 = 2.6 N
do we have that much?
weight = m g = 1.25 * 9.81
so max friction = .3*1.25*9.81 = 3.68 N
so
no slip :)
A block with mass M = 5.00 kg rests on a frictionless table and is attached by a
horizontal spring (k = 130 N/m) to a wall. A second block, of mass m = 1.25 kg rests on top of M.
The blocks are displaced by 10 cm then released.
If the coefficient of static friction between the two blocks
is 0.3, does block m slip off block M? (Show your work)
YES / NO
5 answers
Thank you so much!
You are welcome :)
Just to clarify, when you conclude that the block m doesn't slip, which forces are you comparing? If the friction was smaller than the force required to accelerate the small block, would it then slip?
Yes, if the friction was less than the force required to accelerate the upper block, it would accelerate more slowly than the bottom one. In other words slip :)
0 answers