Asked by Sue

A block with mass M = 5.00 kg rests on a frictionless table and is attached by a
horizontal spring (k = 130 N/m) to a wall. A second block, of mass m = 1.25 kg rests on top of M.
The blocks are displaced by 10 cm then released.
If the coefficient of static friction between the two blocks
is 0.3, does block m slip off block M? (Show your work)
YES / NO

Answers

Answered by Damon
F = - k x
= -130 (.1) = -13 N

if they do not slip m = 6.25 kg

a = 13/6.25 = 2.08 m/s^2

force required to accelerate small block = 1.25 *2.08 = 2.6 N

do we have that much?
weight = m g = 1.25 * 9.81
so max friction = .3*1.25*9.81 = 3.68 N
so
no slip :)
Answered by Sue
Thank you so much!
Answered by Damon
You are welcome :)
Answered by Sue
Just to clarify, when you conclude that the block m doesn't slip, which forces are you comparing? If the friction was smaller than the force required to accelerate the small block, would it then slip?
Answered by Damon
Yes, if the friction was less than the force required to accelerate the upper block, it would accelerate more slowly than the bottom one. In other words slip :)
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