Asked by Tim
A 275-gram ball bounces off a wall. The ball stays in a horizontal plane throughout the motion. The ball strikes the wall with a speed of 4.50 m/s at an angle of 𝜃 = 35.0o relative to the wall and rebounds with the same speed at the same angle. If the ball is in contact with the wall for 8.00 ms, calculate the average force exerted on the wall by the ball. (Determine both the magnitude and direction of this force.)
Answers
Answered by
Damon
change in x momentum = 2 * mass * x velocity
= 2 * .275 * 4.5 sin 35
force on ball by wall = change in momentum /time
= change in momentum/.008
wall on ball is -x so ball on wall is + x direction
= 2 * .275 * 4.5 sin 35
force on ball by wall = change in momentum /time
= change in momentum/.008
wall on ball is -x so ball on wall is + x direction
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