Asked by Sahara
A launched rocket has an altitude, in meters, given by the polynomial h+vt-4.9t^2, where h is the height, in meters, from which the launch occurs, at the velocity v in meters per second, and the t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 150 meters high with an initial upward speed of 60 meters per second, what will its height be after 4 seconds?
Answers
Answered by
etutorphysics
h=150m
v=60m/s
t=4s
height of rocket=h+vt-4.9t^2
=150+(60x4)-4.9x4^2
=311.6m
v=60m/s
t=4s
height of rocket=h+vt-4.9t^2
=150+(60x4)-4.9x4^2
=311.6m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.