Question
Transform the quadratic equation to a standard form.
4x^2-y^2-24x-10y+11=0
My answer:
4(x-3)^2 - (y+5)^2 = 0
Therefore, this is a degenerate conic section, right?
4x^2-y^2-24x-10y+11=0
My answer:
4(x-3)^2 - (y+5)^2 = 0
Therefore, this is a degenerate conic section, right?
Answers
Steve
4x^2-y^2-24x-10y+11=0
4(x^2-6x) - (y^2+10y) = -11
4(x^2-6x+9) - (y^2+10y+25) = -11 + 4(9) + 25
4(x-3)^2 - (y+5)^2 = 50
Better check to see what you lost while completing those squares.
4(x^2-6x) - (y^2+10y) = -11
4(x^2-6x+9) - (y^2+10y+25) = -11 + 4(9) + 25
4(x-3)^2 - (y+5)^2 = 50
Better check to see what you lost while completing those squares.