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1500 cm^3 of ideal gas at STP is cooled to -20°C and put into a 1000 cm^3 container. What is the final gauge pressure? 1-11 kPa...Asked by lila
1500 cm3 of ideal gas at STP is cooled to -20°C and put into a 1000 cm3 container. What is the final gauge pressure?
11 kPa
40 kPa
113 kPa
141 kPa
240 kPa
11 kPa
40 kPa
113 kPa
141 kPa
240 kPa
Answers
Answered by
bobpursley
absolute pressure=101.3kpa(273-20)/273*1500/1000
Gauge pressure=absolute-atmospheric.
determine
So just estiamting, answer b is in the ballpark.
Gauge pressure=absolute-atmospheric.
determine
So just estiamting, answer b is in the ballpark.
Answered by
Damon
a liter is 10^3 = 1000 cm^3
so we have 22.4 * 1.5 = 33.6 moles of gas at 273 deg K and 100 kPa
P V = n R T
n and r remain the same
so
P1V1/T1 = P2V2/T2
100 (1500)/273 = P2 (1000)/253
P2 = 139 kPa ABSOLUTE pressure
- 100 KPa for gage
= 39 k Pa gage
so we have 22.4 * 1.5 = 33.6 moles of gas at 273 deg K and 100 kPa
P V = n R T
n and r remain the same
so
P1V1/T1 = P2V2/T2
100 (1500)/273 = P2 (1000)/253
P2 = 139 kPa ABSOLUTE pressure
- 100 KPa for gage
= 39 k Pa gage
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