Find the mean and standard deviation of the data set. If necessary, round to the nearest hundredth.
4, 8, 5, 12, 3, 9, 5, 2
Mean is 6 and standard deviation is about 13.33?
5 answers
That standard deviation is much too big. Are you sure it is not the variance and you forgot to take the square root?
Oops! I forgot the square root. So would the standard variation be 3.65?
mean is 6 yes
I get sqrt 80 = 8.94 for SD
2^2 + 2^2+1^2+6^2+3^2+3^2+1^2+4^2
4+4+1+36+9+9+1+16 = 80
sqrt 80 = 8.94
I get sqrt 80 = 8.94 for SD
2^2 + 2^2+1^2+6^2+3^2+3^2+1^2+4^2
4+4+1+36+9+9+1+16 = 80
sqrt 80 = 8.94
Damon, I think you forgot to divide by 7 before taking the square root.
SD = √(80/7) = 3.3806
The amazing Wolfram supports this
http://www.wolframalpha.com/input/?i=standard+deviation+4%2C+8%2C+5%2C+12%2C+3%2C+9%2C+5%2C+2
SD = √(80/7) = 3.3806
The amazing Wolfram supports this
http://www.wolframalpha.com/input/?i=standard+deviation+4%2C+8%2C+5%2C+12%2C+3%2C+9%2C+5%2C+2
whoops, sorry, thanks !
4 answers