Asked by bex
Evaluate the integral of 4x^2(2+x^3)^9 dx.
I'm supposed to use the substitution rule but I have absolutely no idea where to start with this problem.
I'm supposed to use the substitution rule but I have absolutely no idea where to start with this problem.
Answers
Answered by
Count Iblis
You just look at the expression and then try defining a function u(x) such that in terms of u the integral will simplify. There is no "wrong choice" because the integral in terms of u will always be the same as the original one. However, the goal is to evaluate the integral, so it's only useful when it simplifies.
In this case, the (1+x^3)^9 factor makes the integral complicated. If you define:
u(x) = 1+x^3
then
du = (du/dx) dx = 3x^2 dx
Therefore:
4x^2(2+x^3)^9 dx =
(2+x^3)^9 4/3 3 x^2 dx =
4/3 u^9 du
I think you can integrate this easily.
In this case, the (1+x^3)^9 factor makes the integral complicated. If you define:
u(x) = 1+x^3
then
du = (du/dx) dx = 3x^2 dx
Therefore:
4x^2(2+x^3)^9 dx =
(2+x^3)^9 4/3 3 x^2 dx =
4/3 u^9 du
I think you can integrate this easily.
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