Question
DIRECTIONS ARE.
WRITE THE EQUATION OF THE LINE L satisfying the given geometric conditions.
Problem is:
L has y-intercept (0,-3) and is parallel to the line with equation
y=(2/3)x +1.
So, this is what i did:
Y=(2/3)x+b....it passes through (0,-3)
-3=b
so, the equation is:
y=(2/3)x-3
then problem number 2:
L has y-intercept (0,2) and is perpendicular to the line with equation 2x-3y=6.
so this is whati did:
3x+2y=K..it passes through (0,2)
2(2)=k
4=k
so the equation would be:
3x+2y=4
first is correct.
second correct.
thank you for helping me out.
WRITE THE EQUATION OF THE LINE L satisfying the given geometric conditions.
Problem is:
L has y-intercept (0,-3) and is parallel to the line with equation
y=(2/3)x +1.
So, this is what i did:
Y=(2/3)x+b....it passes through (0,-3)
-3=b
so, the equation is:
y=(2/3)x-3
then problem number 2:
L has y-intercept (0,2) and is perpendicular to the line with equation 2x-3y=6.
so this is whati did:
3x+2y=K..it passes through (0,2)
2(2)=k
4=k
so the equation would be:
3x+2y=4
first is correct.
second correct.
thank you for helping me out.
Answers
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