Assume L for length of stick.
Put the fulcrum at x from the 500-g mass.
The centre of gravity of the stick is at the centre, L/2, where the mass is assumed to concentrate.
Take moments about the fulcrum:
500*x=200*(L/2-x)
Solve for x in terms of L:
x=L/7
Suppose the mass of the stick is 200 g, and a single 500-g mass is to play "solitary seesaw" at the 0-cm mark. Where should the fulcrum be located?
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