Question
Use the Laws of logarithms to rewrite the expression log(1000000x^19)in a form with no logarithm of a product, quotient or power.
After rewriting we have log(1000000x^19)= A + Blog(x)?
I know B = 19, but what's A?
After rewriting we have log(1000000x^19)= A + Blog(x)?
I know B = 19, but what's A?
Answers
log(1000000x^19)
= log(10^6)+log(x^19)
= 6 + 19logx
assuming logs base 10 :-)
= log(10^6)+log(x^19)
= 6 + 19logx
assuming logs base 10 :-)
thank you!
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