Asked by Jarron
what is the volume of a triangular pyramid with the length of 9 inches, a height of 4 inches, and a width of 6 inches?
Answers
Answered by
Henry
Ab =
Ab = (W*L)/2 = (6*9)/2 = 27 in^2 = Area
of the base.
V = (Ab*h)/3 = (27*4)/3 = 36 in^3.
Ab = (W*L)/2 = (6*9)/2 = 27 in^2 = Area
of the base.
V = (Ab*h)/3 = (27*4)/3 = 36 in^3.
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