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How to figure out the temperature of a lake using x for the feet or the Depth and for the degrees Celsius use (3900x+1000)/(3x^...Asked by beckylynn
How to figure out the temperature of a lake using x for the feet or the Depth and for the degrees Celsius, use (3900x+1000) /(3x^2+100) with the answer of the degrees Celsius being 6.74 looking like
6.74=(3900x+1000)/(3x^2+100)
i need the depth
i have figure out that
a=-20.22
b= 3900
c= 326
On the quadratic formula table
-3900+Square root ()/-40.44
6.74=(3900x+1000)/(3x^2+100)
i need the depth
i have figure out that
a=-20.22
b= 3900
c= 326
On the quadratic formula table
-3900+Square root ()/-40.44
Answers
Answered by
MathMate
Yes, the quadratic formula is:
x=(-b±√(b²-4ac))/(2a)
what you need inside the square-root sign is
b²-4ac
x=(-b±√(b²-4ac))/(2a)
what you need inside the square-root sign is
b²-4ac
Answered by
MathMate
You will get two roots for x.
Reject the negative one, and retain the positive root which is a little under 200.
Reject the negative one, and retain the positive root which is a little under 200.
Answered by
beckylynn
Thank you
My professor told me to go to the math lab and they could help on a white board thank you for all you help if I knew going back to school I wouldn't have done it at the wise age of 60
My professor told me to go to the math lab and they could help on a white board thank you for all you help if I knew going back to school I wouldn't have done it at the wise age of 60
Answered by
MathMate
No problem.
Let us know any time if you need further help.
Let us know any time if you need further help.
Answered by
beckylynn
i do that just confused me even more
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