Use c1v1=c2v2
c1=230 g/L
c2=200 g/L
v2=2 L
Solve for v1.
Water to be added equals v2 - v1=2L - v1
a chemist has a supply of cuso4 solution that contains 230 gram per litre of water. she wishes to make a copper sulphate solution that has a solution of 200.0 grams per litre gow ,uch of her copper sulphate solution should she use and how much water should be added to make exactly 2 litres of the weaker copper solution?
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